Question

5.(×-2)=3.(×+4)+6 me ajudem pvvr ​

Answer 1

$5x (x-2)= 3x (x +4) +6\\5x^2-10x = 3x(x+4)+6\\5x^2-10x=3x^2+12x+6\\5x^2-10x-(3x^2+12x+6)=0\\5x^2-10x-3x^2-12x-6=0\\2x^2-10x-12x-6=0\\2x^-22x-6=0\\2(x^2-11x-3)=0\\x^2-11x-3=0\\x =\frac{-b\pm\sqrt{b^2-4ac} }{2a}\\a=1\\b=-11\\c=-3\\x= \frac{-(-11)\pm\sqrt{(-11)^2-4x1(-3)} }{2.1}\\x= \frac{11\pm\sqrt{121-4.1(-3)} }{2.1}\\x= \frac{11\pm\sqrt{121+12} }{2.1}\\x= \frac{11\pm\sqrt{133} }{2.1}\\x= \frac{11\pm\sqrt{133} }{2}\\x= \frac{11+\sqrt{133} }{2}\\x= \frac{11-\sqrt{133} }{2}$

$x= \frac{11+\sqrt{133} }{2}\\x= \frac{11-\sqrt{133} }{2}\\x= \frac{11\pm\sqrt{133} }{2}$