Question

(4x³-3 -6x² -4x²-1).(4x+2)

Answer 1

$(4 {x}^{3} - 3 - 6 {x}^{2} - 4 {x}^{2} - 1).(4x + 2) = \\ 16 {x}^{4} - 12x - 24 {x}^{3} - 16 {x}^{3} - \: 4x + 8 {x}^{3} - 6 - 12 {x}^{2} - 8 {x}^{2} - 2$