Question

4x(2x-5)=3x-14 segundo grau

Answer 1

$4x(2x-5)=3x-14$

$4x\cdot2x+4x\cdot(-5)=3x-14$

$8x^2-20x=3x-14$

$8x^2-20x-3x+14=0$

$8x^2-23x+14=0$

Aplicando a fórmula de Bhaskara:

$x=\frac{-(-23)\pm\sqrt{(-23)^2-4\cdot8\cdot14}}{2\cdot8}$

$x=\frac{23\pm\sqrt{529-448}}{16}$

$x=\frac{23\pm\sqrt{81}}{16}$

$x=\frac{23\pm9}{16}$

Tirando daí as soluções $x=7/8$ e $x=2$