Question

48-[-2+(-8)-(-2)+(-12)×(-4)] alguém me ajuda

Answer 1

    $48-[-2+(-8)-(-2)+(-12)\times (-4)]=$

$=48-(-2-8+2+48)=$

$=48-(-10+2+48)=$

$=48-(-8+48)=$

$=48-40=$

$=8$

Answer 2

Resposta:

$48-(-2+(-8)-(-2)+(-12).(-4))\\48-(-2-8-(-2)+(-12).(-4))\\48-(-2-8+2+(-12).(-4))\\48-(-2-8+2+48)\\48-(-8+48)\\48-40\\8$