Question

(4³-6x²+7x+4)÷(ײ-2x-1)​

Answer 1

$({4}^{3} - 6 {x}^{2} + 7x + 4) \div ({x}^{2} - 2x - 1) = \\ \\ (64 - 6 {x }^{2} + 7 x + 4) \div ( {x}^{2} - 2x - 1) = \\ \\ (68 - 6 {x}^{2} + 7x) \div ( {x}^{2} - 2 x - 1) = \\ \\ (6 {x}^{2} + 7x + 68) \div ({x}^{2} - 2x - 1) = \\ \\ \frac{6 {x}^{2} + 7x + 68 }{ {x}^{2} - 2x - 1 }$