Question

4^x >64^x+1 inequação exponencial

Answer 1

$\Large\boxed{\begin{array}{l}\sf4^x>(4^3)^{x+1}\\\sf 4^x>4^{3x+3}\\\sf x>3x+3\\\sf x-3x>3\\\sf -2x>3\cdot(-1)\\\sf 2x<-3\\\sf x<-\dfrac{3}{2}\\\\\sf S=\bigg\{x\in\mathbb{R}/x<-\dfrac{3}{2}\bigg\}\end{array}}$