Question

4- Determine X tal que :
a) 0° < X < 360° e cos x = 1/2
b) 0 < x < 2π e cos x = - √2/2

Answer 1

a) cosx=1/2
1° e 4° Quadrante
x=60° = π/3
x=300° = 5π/3
S{π/3, 5π/4}

b) cosx=-√2/2
2° e 3° Quadrante
x=135° = 135π/180=3π/4
x=225° = 225π/180=5π/4
S{3π/4, 5π/4}

espero ter ajudado

Answer 2

Determine x tal que cosx=−3√2.

vc sabe essa ?