Question

4. Calcule a massa de 4.6.10 ^ 24 mol de monóxido de carbono (CO_{2}) . Dados: Constante de Avogadro: 6,0. 10 ^ 23 / mol ; Massas Molares (g / mol) : C = 12eO = 16​

Answer 1

$\large\boxed{\begin{array}{l}\sf m_{CO_2}=12+2\cdot16=12+32=44\,g/mol\\\sf 44\,g\longrightarrow 6\cdot10^{23}\,mols\\\sf x\longrightarrow 4\cdot6\cdot10^{24}\\\sf 6\cdot10^{23}\cdot x=44\cdot4\cdot6\cdot10^{24}\\\\\sf x=\dfrac{44\cdot4\cdot\diagup\!\!\!\!6\cdot10^{24}}{\diagup\!\!\!\!6\cdot10^{23}}\\\\\sf x=176\cdot10^{24-23}\\\sf x=176\cdot10\\\sf x=1760\,g\end{array}}$