Question

4 (5×-3) +64 (3-×)-3 (12×-4)=96

Answer 1

20x-12+192-64x-36x+12-96=0
20x-100x=-96
-80x=-96
x=96/80
x=6/5

Answer 2

$4(5x-3)+64(3-x)-3(12x-4)=96 \\ 20x-12+192-64x-36x+12=96 \\ -80x+192=96 \\ 80x=192-96 \\ x = \frac{96}{80} = \frac{6}{5} =1,2$