Question

(3x³+5x²+x-3)+(x³-3x²+2x+4)
(4x³-4x²+2x+1)+(2x³-3x²+x+2)
(-x²+2xy+y²+2)+(x²-2xy+y²-2)
(-x²-2xy-y²-1)-(-x²-2xy+y²+1)
alguém me ajuda!

Answer 1

(3x³ + 5x² + x - 3) + (x³ - 3x² + 2x + 4) = 3x³ + x³ + 5x² -3x² + x + 2x - 3 + 4=

4x³ + 2x² + 3x + 1

(4x³ - 4x² + 2x + 1)+(2x³ - 3x² + x + 2) = 4x³ + 2x³ -4x² - 3x² + 2x + x +1 + 2 =

6x³ - 7x² + 3x + 3

(-x²+2xy+y²+2)+(x²-2xy+y²-2) = -x²+x²+y²+y²+2xy-2xy+2-2=

2y²

(-x²-2xy-y²-1)-(-x²-2xy+y²+1) = -x²+x²-2xy+2xy-y²-y²-1-1 =

-2y² - 2 = -2 (y² + 1)