Question

3x² – 7x + 4 = 0 ???

Answer 1

Utilizando o método de Baskhara

A=3
B=-7
C=4

Delta= b²-4(a)(c)
Delta= 49-4(3)(4)
Delta=1

$\frac{ - b + - \sqrt{1} }{6}$
Então
X1=
$\frac{7 + 1}{6} = \frac{8}{6} = \frac{4}{3}$
X2=
$\frac{7 - 1}{6} = \frac{6}{6} = 1$

Answer 2

${3x}^{2} - 7x + 4 = 0$
a = 3, b = -7 e c = 4

Delta:
$( { - b)}^{2} - 4.(a).(c)$
$( { - 7)}^{2} - 4 \times 3 \times 4$
49 - 4 × 3 × 4
49 - 4 × 12
49 - 48
Delta = 1