Question

3x²+4=13x por bhaskara

Answer 1

3x^2+4=13x
3x^2-13x+4=0
delta=b^2-4ac
delta=(-13)^2-4.3.4
delta=169-48
delta=121
x=-b-/+ raiz de delta/2a
x=-(-13)-11/2.3
x=13-11/6
x=2/6 (:2)
x=1/3
x=-(-13)+11/2.3
x=13+11/6
x=24/6
x=4

Answer 2

Primeiro vamos igualar essa equação a zero:

$3x^2-13x+4=0$

Depois, encontrar o Delta, sendo:

$a=3,~b=-13,~c=4$

$\Delta~=b^2-4.a.c \\ \Delta~=(-13)^2-4.3.4 \\ \Delta~=169-48 \\ \Delta~=121$

Agora, resolveremos por Bháskara:

$x= \frac{-b\pm \sqrt{\Delta~}}{2.a} \\ \\ x= \frac{13\pm \sqrt{121}}{2.3} \\ \\ x= \frac{13\pm11}{6} \\ \\ x'= \frac{13+11}{6}= \frac{24}{6}=4 \\ \\ x''= \frac{13-11}{6}= \frac{2}{6}:2= \frac{1}{3}$

$S=\{\frac{1}{3},~4\}$