Question

3x ao quandrado-5x+14-x ao quadrado-10x+2=0

Answer 1

Resposta:

Explicação passo a passo:

3x²-5x+14-x²-10x+2=0

2x²-15x+16=0

a=2

b=-15

c=16

x=15+-V(-15)²-4.2.16/2.2

x=15+-V225-128/4

x=15+-V97/4

x'=15+V97/4

x''=15-V97/4

Answer 2

Resposta:

$3x^2-5x+14-x^2-10x+2=0\\ \\ 3x^2-x^2-5x-10x+14+2=0\\ \\ 2x^2-15x+16=0$

coeficientes:

$a=2\\ b=-15\\ c=16\\ \\ \\ \Delta=b^2-4ac\\ \Delta=(-15)^2-4(2)(16)\\ \Delta=225-128\\ \\ \Delta=97$

$x=\dfrac{-b\pm\sqrt{\Delta} }{2a}\\ \\ \\ x=\dfrac{-(-15)\pm\sqrt{97} }{2(2)}=\dfrac{15\pm\sqrt{97}} {4}\\ \\ \\\boxed{ x'=\dfrac{15+\sqrt{97} }{4}}\\ \\ \\ \boxed{x"=\dfrac{15-\sqrt{97} }{4}}$