Question

(3x+4y)³ Não estou conseguindo resolver

Answer 1

Resposta:

Explicação passo-a-passo:

Vamos desenvolver (3x + 4y)³ pela teoria binomial. Assim:

$(3x+4y)^{3}=\binom{3}{0}(3x)^{3}+\binom{3}{1}(3x)^{2}(4y)+\binom{3}{2}(3x)(4y)^{2}+\binom{3}{3}(4y)^{3}$ =>

$(3x+4y)^{3}=\frac{3!}{(3-0)!.0!}(3x)^{3}+\frac{3!}{(3-1)!.1!}(3x)^{2}(4y)+\frac{3!}{(3-2)!.2!}(3x)(4y)^{2}+\frac{3!}{(3-3)!.3!}(4y)^{3}$ =>

$(3x+4y)^{3}=1.27x^{3}+3.9x^{2}.4y+3.3x.16y^{2}+1.64y^{3}$ =>

$(3x+4y)^{3}=27x^{3}+108x^{2}y+144xy^{2}+64y^{3}$.