Matemática, perguntado por consueloguadalupe819, 7 meses atrás

34 Considerando a = 23.32, 6 = 22.5 e c= 2.33 calcule: a) mmc(a, b) c) mmc(b, c) b) mmc(a,0) d) mmc(a, b, c)​

Soluções para a tarefa

Respondido por jessejustt
2

Resposta:

Resposta:

Explicação passo a passo:

\begin{gathered}a = 2^{3} .3^{2} \\b = 2^{2} .5\\c=2.3^{3}\end{gathered}

a=2

3

.3

2

b=2

2

.5

c=2.3

3

a)

\begin{gathered}mmc(a,b) = 2^{3} .3^{2} .5\\mmc(a,b) = 8.9.5\\mmc(a,b)=360\end{gathered}

mmc(a,b)=2

3

.3

2

.5

mmc(a,b)=8.9.5

mmc(a,b)=360

b)

\begin{gathered}mmc(a,c) = 2^{3} .3^{3} \\mmc(a,c) = 8.27\\mmc(a,c) = 216\end{gathered}

mmc(a,c)=2

3

.3

3

mmc(a,c)=8.27

mmc(a,c)=216

c)

\begin{gathered}mmc(b,c)=2^{2} .3^{3} .5\\mmc(b,c)=4.27.5\\mmc(b,c)=540\end{gathered}

mmc(b,c)=2

2

.3

3

.5

mmc(b,c)=4.27.5

mmc(b,c)=540

d)

\begin{gathered}mmc(a,b,c) = 2^{3} .3^{3} .5\\mmc(a,b,c)= 8.27.5\\mmc(a,b,c) =1080\end{gathered}

mmc(a,b,c)=2

3

.3

3

.5

mmc(a,b,c)=8.27.5

mmc(a,b,c)=1080


consueloguadalupe819: obrigado
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