Question

3$x^{2}$-7x+4=0

Answer 1

$3 x^{2} - 7x + 4 = 0 \\ \\ \Delta = (-7)^2 - 4.3.4 \\ \Delta = 1 \\ \\ x = \frac{-(-7) \pm \sqrt{1} }{2.3} = \frac{7 \pm 1}{6} \\ \\ x' = \frac{7+1}{6} = \frac{8}{6} = \boxed{\frac{4}{3}} \\ \\ x'' = \frac{7-1}{6} = \frac{6}{6} = \boxed{1} \\ \\ \boxed {S = \{ \frac{4}{3};1\}}$