Question

3-Simplifique os radicais:
a)⁶√128x⁶y⁸ =____
b)√12ab¹⁰ +____
c)³√2¹² =____
d)⁷√y¹⁹ =____
ME AJUDEM POR FAVOO É PRA AMANHÃ..... AJUDAAA....

Answer 1

$\Large\boxed{\begin{array}{l}\rm Simplifique~os~radicais:\\\tt a)~\sf\sqrt[\sf6]{\sf 128x^6y^8}\\\tt b)~\sf\sqrt{12ab^{10}}\\\tt c)~\sf\sqrt[\sf3]{\sf 2^{12}}\\\tt d)~\sf\sqrt[\sf7]{\sf y^{19}}\end{array}}$

$\Large\boxed{\begin{array}{l}\tt a)~\sf\sqrt[\sf6]{\sf128x^6y^8}=\sqrt[\sf6]{\sf 2^6\cdot x^6\cdot y^6\cdot y^2}=2xy\sqrt[\sf6\div2]{\sf y^{2\div2}}\\\sf=2xy\sqrt[\sf3]{\sf y}\\\tt b)~\sf\sqrt{12ab^{10}}=\sqrt{2^2\cdot3\cdot a\cdot (b^5)^2}=2b^5\sqrt{3a}\\\tt c)~\sf\sqrt[\sf3]{\sf 2^{12}}=\sqrt[\sf3]{\sf (2^4)^3}=2^4=16\\\tt d)~\sf\sqrt[\sf7]{\sf y^{19}}=\sqrt[\sf7]{\sf(y^2)^7\cdot y^5}=y^2\sqrt[\sf7]{\sf y^5}\end{array}}$