Question

3) Resolva as equações do 2º grau em R.

a) 12x² = 0

b)x² + 10x = 0

c) 5x²- 20x = 0

d) x² - 169 = 0

e)-2x² + 800 = 0

f) x²-x-6= 0

g) x² + 7x + 10 = 0

h) 5x² + 4x +3=0

i)-2x²-12x - 16 = 0

j) 3x² - 6x + 3 = 0

Answer 1

Resposta:a) x² - 7x = 0

x(x-7) = 0,   x = 0 ou:

x-7 = 0

x = 7

b)x² +5x = 0

x(x+5) = 0, x = 0 ou:

x + 5 = 0

x = -5

c)4x² - 9x = 0

x(4x-9) = 0, x = 0 ou:

4x - 9 = 0

4x = 9

x = 9/4

d)3x² +5x = 0

x(3x+5) = 0, x = 0 ou:

3x +5 = 0

3x = -5

x = -5/3

e)4x²-12x = 0

4x(x-3) = 0, x = 0 ou:

x -3 = 0

x = 3

f)5x²+x = 0

x(5x+1) = 0, x = 0 ou:

5x + 1 = 0

5x = -1

x = -1/5

g)x²+x = 0

x(x+1) = 0, x = 0 ou:

x + 1 = 0

x = -1

h)7x²-x = 0

x(7x-1) = 0, x = 0 ou:

7x -1 = 0

7x = 1

x = 1/7

i)2x² = 7x

2x²-7x = 0

x(2x - 7) = 0, x = 0 ou:

2x -7 = 0

x = 7/2

j)2x² = 8x

2x² -8x = 0

2x(x-4) = 0, x = 0 ou:

x - 4 = 0

x = 4

k)7x² = -14x

7x² +14x = 0

7x(x+2) = 0, x = 0 ou:

x + 2 = 0

x = -2

l) -2x² +10x = 0

-2x(x+5) = 0, x = 0 ou:

x + 5 = 0

x = -5

Explicação passo-a-passo: