Question

3. Quantos mols há em 8,6 x 1023 moléculas de CO2?

Answer 1

$\boxed{\begin{array}{l}\sf 1~mol~de~CO_2\longrightarrow 6\cdot10^{23}~mol\acute eculas\\\sf x\longrightarrow 8,6\cdot10^{23}~mol\acute eculas\\\sf 6\cdot10^{23} x=8,6\cdot10^{23}\\\sf x=\dfrac{8,6\cdot\diagdown\!\!\!\!\!\!10^{23}}{6\cdot\diagdown\!\!\!\!\!10^{23}}\\\sf x=1,43~mols~de~CO_2\end{array}}$