Question

(3+j4)/(5<53,13°) fomar retangular

Answer 1

Resposta:

z=(3+j4)/(5∠53,13°)=z1/5∠53,13°

z1= 3+j4

|z1|=√3²+4²=√9+16=√25=5

α=arccos3/5=53,13°

z1= 3+j4 = 5∠53,13°

z=5∠53,13°/5∠53,13°=1∠0°