Question

3) Determine as coordenadas do ponto médio a) A (3,-2) e B (-1,-6) b) A (1,-7) e B (3,-5) c) A (-1,5) e B (5,-2) d) A (1/2, 1/3) e B ( -1, 2/3) *

Answer 1

Olá, boa tarde!

          $\searrow$

• Os pontos médios são:

a) (1,-4);

b) (2,-6);

c) (2,3/2);

d) (-1/4,1/2)

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( PONTO MÉDIO )

      $\searrow \searrow$

 Para determinarmos um ponto médio precisamos somar os extremos e dividir o resultado por 2.

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Sua questão:

A) Distância entre os pontos A (3,-2) e B (-1,-6):

$\begin{array}{lr} \sf 2M = ( 3, -2 ) + ( -1, -6 )\\\\\sf 2M = ( 2, - 8)\\\\\sf 2M = (\frac{2}{2} ,-\frac{8}{2} )\\\\\sf M = (1,-4).\end{array}$

B) Distância entre os pontos A (1,-7) e B (3,-5) :

$\begin{array}{lr} \sf 2M = ( 1, -7 ) + ( 3, -5 )\\\\\sf 2M = ( 4, - 12)\\\\\sf 2M = (\frac{4}{2} ,-\frac{12}{2} )\\\\\sf M = (2,-6).\end{array}$

C) Distância entre os pontos A (-1,5) e B (5,-2):

$\begin{array}{lr} \sf 2M = ( -1, 5 ) + ( 5, -2 )\\\\\sf 2M = ( 4, 3)\\\\\sf 2M = (\frac{4}{2} ,\frac{3}{2} )\\\\\sf M = (2,\frac{3}{2} ).\end{array}$

D) Distância entre os pontos A (1/2, 1/3) e B ( -1, 2/3):

$\begin{array}{lr} \sf 2M = ( \frac{1}{2},\frac{1}{3} ) + ( -1, \frac{2}{3} )\\\\\sf 2M = ( \frac{1}{2} + (-1) , \frac{1}{3}+ \frac{2}{3} )\\\\\sf 2M = (-\frac{1}{2} \div 2,\frac{3}{3}\div2 )\\\\\sf M = (-\frac{1}{4} ,\frac{1}{2} ).\end{array}$

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$\checkmark$ Espero ter ajudado!

$\checkmark$ Bons estudos!

$\Large\begin{matrix} \underbrace{ \sf By: Pedro } \end{matrix}$