Question

3) Aplique a propriedade distributiva e agrupe os termos semelhantes
a) (x + 2) . (2x – 5) = b) (x +3) . ( x – 1) = c) (2x – 2) . ( x + 3) =

Answer 1

A) (x + 2) . (2x – 5)

2x²-5x+4x-10

R= 2x²-1x-10

B) (x +3) . ( x – 1)

X²-x+3x-3

R= X²+3x-3

C) (2x – 2) . ( x + 3)

2x²+6x-2x-6

R= 2x²+4x-6.

Espero ter ajudado :)