Question

(^3√-8 +3)^2 - {2-[√(¹'9)^-1 -12] }

Answer 1

Resposta:

Explicação passo-a-passo:

(raiz cúbica de -8 + 3)² - {2 - [ (V9)^-1 -12]}=

(-2+3)²- {2 - [ (3)^-1 -12]}=

(1)² - {2 -[1/3-12]}=

1 - { 2 - [1/3-36/3]}=

1 - {2 -[-35/3]}=

1 - {2 +35/3}=

1 - {6/3 + 35/3}=

1-{41/3}=

1-41/3=

3/3-41/3=

-38/3