Question

√3.(√18+√32)-√144:√19

Answer 1

$\sqrt{3} \times ( \sqrt{18} + \sqrt{32} ) - \sqrt{144} \div \sqrt{19} \\ \sqrt{3} \times ( \sqrt{18} + 4 \sqrt{2} ) - 12 \div \sqrt{19} \\ \sqrt{3} \times 7 \sqrt{2} - \frac{12 \sqrt{19} }{19} \\ 7 \sqrt{6} - \frac{12 \sqrt{19} }{19} \\ \\ Espero \: ter \: ajudado! \:$