Question

(×3+1/4mn)2

(1/3a2-3/2b2)2

(2x3+5y3)2

me ajudem ​

Answer 1

Resposta:

Explicação passo a passo:

A)

(×^3+1/4mn)^2

=

(X^3)^2 + 2.x^3.1/4.mn +(1/4mn)^2

=

X^6 + 1/2. x^3.m.n + 1/16 m^2.n^2

B)

(1/3a^2 - 3/2b^2)2

= (1/3 a^2)^2 - 2.1/3.3/2.a^2.b^2 + (3/2 b^2)^2

= 1/9 a^4 - 2/3.3/2.a^2.b^2 +9/4.b^4

= 1/9 a^4 - a^2.b^2 + 9/4 b^4

C)

(2x^3+5y^3)^2

= (2x^3)^2 + 2.2x^3.5y^3 + (5y^3)^2

= 4x^6 + 20x^3.y^3 + 25y^6