Question

-2y² + 32 = 0 como resolvo isso

Answer 1

-2y² = -32
2y² = 32
y² = 16
y = √16
y = +-4

Answer 2

Δ=b²-4ac
Δ=0²-4(-2)(32)
Δ=8×32
Δ=256


x₁= -b+√Δ/2a
 x₁=0+16/-4
x₁= -4



x₂= -b-√Δ/2a
x₂= 0-16/-4
x₂= 4


S={-4,4}