Question

-2x²+10x+12=0

4x²-4x-8=0

Answer 1

Resposta:

∆= b^2 - 4ac

X = -b ± √∆ / 2a

A) -2x^2 + 10x +12 = 0

∆ = 10^2 -(4*(-2)*(12))

∆ = 100 + 96

∆ = 196

X = -10 ± √196 / 2*(-2)

X = -10 ± 14 /-4

X' = 4 / -4 = -1

X'' = -24 / -4 = +6

B) 4x² - 4x - 8 = 0

∆ = (-4)^2 - (4*(4)*(-8))

∆ = 16 + 128∆ = 144

X = +4 ± √144 / 2(4)

X = +4 ± 12 / 8

X' = 16 / 8 = 2

X'' = -24 / -4 = +6