Question

(2x + xy)²

(x² + 1)²

(x + 2y)²

(x³ + 1/3)²

Answer 1

1) 4x² + 4xy + x²y²

2) x^4-2x²+1

3)x²-4xy+4y²

4)x³-1/3, sendo (√3)²×=27

Answer 2

= (2x + xy)²
= (2x)^2 + 2x.xy + (xy)^2
= 4x^2 + 2x^2y + x^2 y^2

= (x² + 1)²
= (x^2)^2 +2.1.x^2 + 1^2
= x^4 + 2x^2 + 1

= (x + 2y)²
= x^2 + 2.x.2y + (2y)^2
= x^2 + 4xy + 4y^2

= (x³ + 1/3)²
= (x^3)2+2.x^3. 1/3 + (1/3)^2
= x^6 + 2x^3/3+ 1/9