Question

(2x+8) (4x+1) me ajudem a resolver

Answer 1

Cálculo

(2x + 8).(4x + 1)
2x.(4x + 1) + 8.(4x + 1)
8x² + 2x + 32x + 8
8x² + 34x + 8

Resposta: 8x² + 34x + 8.

Answer 2

(2x+8).(4x+1)=0

4x.2x+2x.1+4x.8+8.1=0

8x²+2x+32x+8=0

8x²+34x+8=0

Δ=34²-4.8.8

Δ=1156-256

Δ=900

X=-34+-√900/2.8

X1=-34+30/16

X1=-4/16

X1=-1/4

X2=-34-30/16

X2=-64/16

X2=-4