Question

2x-3y-z=4
-7y-3z=-2
-2z=-6
Como resolvo isso?

Answer 1

$2x-3y-z=4 \\-7y-3z=-2 \\-2z=-6 \\ \\z= \frac{-6}{-2} \\z=3 \\ \\-7y= -2+3z \\-7y= -2+3*3 \\-7y= -2+9 \\-7y= +7 \\y= \frac{+7}{-7} \\y=-1 \\ \\ 2x-3y-z=4 \\2x-3*(-1)-3=4 \\2x+3-3=4 \\2x=4 \\x= \frac{4}{2} \\x=2$