Question

2log2(x)+log2(3)−log2(x−1)=log2(6)+log2(x)

Answer 1

log2(x)^2+log2(3)−log2(x−1)=log2(6)+log2(x)log2 (3x^2)/ (x-1) = log 2 (6x)
(3x^2)/ (x-1) = 6 x 
(3x^2)= 6x ( x - 1)
3x^2 = 6x^2 - 6x
3x^2 - 6x = 0
3x ( x - 6) = 0
x= 0 não serve
x= 6