Question

28+{13-[6-(4+1)+2}-}

Answer 1

Resposta:

$28+\{13-[6-(4+1)+2]\}=\\ \\ 28+\{13-[6-5+2]\}=\\ \\ 28+\{13-[8-5]\}=\\ \\ 28+\{13-[3]\}=\\ \\ 28+\{13-3\}=\\ \\ 28+\{10\}=\\ \\ 28+10=38$