Question

2240L de um gás nas CNTP ira possuir quantas moléculas?

Answer 1

nas CTNPs

1 mol --- 22,4 L
    x    --- 2240 L

x = 100 mol

    1 mol --- $6.10^{23} \ moleculas$
100 mol --- y

y = $600.10^{23} \ moleculas = 6.10^{25} \ moleculas$