Question

2°) Resolva as Equações: I) x² – 5x + 6 = 0. cálculo II) 4x² – 4x + 1 = 0. cálculo III) x² + 6x + 7 = 0 cálculo

Answer 1

Resposta:

I)  [ 2 ; 3 ]

II)  [ 1/2 ; 0,5 ]

III) [ - 3 - raiz2 ; -3 + raiz2 ]

Answer 2

Resposta:

Resolvendo por Bhaskara:

x = (b² ± √delta) / 2a

delta = b² - 4ac

I) x² – 5x + 6 = 0

delta = 25 - 24 = 1

x = (5 +- 1) / 2

x' = 3;  x'' = 2

II) 4x² – 4x + 1 = 0

delta = 16 - 16 = 0

x = (4 ± 0) / 8

x' = x'' = 1/2

III) x² + 6x + 7 = 0

delta = 36 - 28 = 8

x = (-6 ± 2√2) / 2

x = -3 ± √2

x' = -3 - √2   ;      x'' = -3 + √2