Question

2 x elevado a dois -8x+8=0

Answer 1

$2x^2-8x+8=0\\ \Delta=b^2-4.a.c\\ \Delta=(-8)^2-4.2.8 \Delta=64-64 \Delta=0\\ x=\displaystyle\frac{-b\pm\sqrt{\Delta}}{2.a}\\ x=\displaystyle\frac{-(-8)\pm\sqrt{0}}{2.2}\\ x=\displaystyle\frac{8}{4}\\ x=2$

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