Question

2(x+3)^2 - 5 (x+3) + 2= 0
e as equações de 2grau... PF

Answer 1

$2(x + 3)^2 - 5(x + 3) + 2 = 0 \\ \\ 2(x^2 + 6x + 9) - 5x - 15x + 2 \\ \\ 2x^2 + 12x - 18 - 5x -13 \\ \\ => 2x^2 + 7x + 5$
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Resolvendo por Bháskara:


$x^{2} + 7x + 5 = 0$

$x = \dfrac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=2, b=7, c=5

Δ=b²−4ac
Δ=(7)²−4*(2)*(5)
Δ=49−40
Δ=9

$x = \dfrac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \dfrac{-7 \pm \sqrt{9}}{2*2} \\ \\ \\ x = \dfrac{-7 \pm 3}{4} \\ \\ \\ x' = \dfrac{-7 + 3}{4} \\ \\ \\ x' = \dfrac{-4}{4} \\ \\ \\ x' = - 1 \\ \\ \\ x'' = \dfrac{-7 - 3}{4} \\ \\ \\ x'' = \dfrac{-10}{4} \\ \\ \\ x'' = -\dfrac{5}{2}$


S = {$-1, \ \ -\dfrac{5}{2}$}