Question

.(2 x ² − 9 x + 2) − (3 x ² + 7 x − 1) polinomios ?

Answer 1

$(2 {x}^{2} - 9x + 2) - (3 {x}^{2} + 7x - 1)$

$2 {x}^{2} - 9x + 2 - 3 {x}^{2} - 7x + 1$

$- {x}^{2} - 16x + 3$

Igualar a zero

$- {x}^{2} - 16x + 3 = 0$

Substituir na equação

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac } }{2a}$

$x = \frac{ - ( - 16) + - \sqrt{ {( - 16)}^{2} - 4 \times ( - 1) \times 3 } }{2 \times ( - 1)}$

$x = \frac{ 16 + - \sqrt{268} }{ - 2}$

$x = \frac{16 + - 2 \sqrt{67} }{ - 2}$

${x}^{.} = - 8 + \sqrt{67}$

${x}^{..} = - 8 - \sqrt{67}$