Question

2) resolva as seguintes equações fracionarias
x+3= 1 + 1-3x
x             2x

Answer 1

$\frac{x+3}{x} = 1 + \frac{1-3x}{2x} \\ \\ \frac{x+3}{x} = \frac{2x+1-3x}{2x}$

2x(x+3) = x(2x+1-3x)

$2 x^{2} + 6x = 2 x^{2} +x-3 x^{2} \\ \\ 2 x^{2} -2 x^{2} +3 x^{2} +6x-x = 0 \\ \\ 3 x^{2} +5x = 0 \\ \\ x(3x+5) = 0 \\ \\ x= 0 \\ \\ 3x+5=0 \\ 3x=-5 \\ \\ x=- \frac{5}{3}$