Question

2) Quais os zeros da função: * f (x) = x² + 7x + 12

Answer 1

Explicação passo-a-passo:

$\sf x^2+7x+12=0$

$\sf \Delta=7^2-4\cdot1\cdot12$

$\sf \Delta=49-48$

$\sf \Delta=1$

$\sf x=\dfrac{-7\pm\sqrt{1}}{2\cdot1}=\dfrac{-7\pm1}{2}$

$\sf x'=\dfrac{-7+1}{2}~\longrightarrow~x'=\dfrac{-6}{2}~\longrightarrow~x'=-3$

$\sf x"=\dfrac{-7-1}{2}~\longrightarrow~x"=\dfrac{-8}{2}~\longrightarrow~x"=-4$

Os zeros da função são $\sf -4$ e $\sf -3$