Question

2) Efetue as Divisões:
a) ( x³ + 2x² + x ) : (+x) =
b) (x² + x³ + x⁴) : (+x²) =
c) (3x⁴ - 6x³ + 10x²) : (-2x²) =
d) (x⁷ + x⁵ + x³) : (-x²) =
e) (3x²y – 18xy²) : (+3xy) =
f) (7x³y – 8x²y²) : (-2xy) =
g) (4x²y + 2xy – 6xy²) : (-2xy) =
h) (20x¹² - 16x⁸ - 8x⁵) : ( +4x⁴) =
i) (3xy⁴ + 9x²y – 12xy²) : (+3xy) =

Answer 1

Resposta:

a) \dfrac{x^3+2x^2+x}{x}=x^2+2x+1

x

x

3

+2x

2

+x

=x

2

+2x+1

b) \dfrac{x^2+x^3+x^4}{x^2}=1+x+x^2

x

2

x

2

+x

3

+x

4

=1+x+x

2

c) \dfrac{3x^4-6x^3+10x^2}{-2x^2}=\dfrac{-3x^2}{2}+3x-5

−2x

2

3x

4

−6x

3

+10x

2

=

2

−3x

2

+3x−5

d) \dfrac{x^7+x^5+x^3}{-x^2}=-x^5-x^3-x

−x

2

x

7

+x

5

+x

3

=−x

5

−x

3

−x