Question

2) Efetue as adiçoes algebricas f) 1/3x^ 2y^2+4/9 x^2 y2^ - 5/6x^2 y^2
g)ay+3/4 ay- 4ay
h)0,9ab^3 + 2,5ab^3 - 5,2ab^3

Answer 1

Resposta:

Explicação passo-a-passo:

f) $\frac{1}{3}x^2y^2+ \frac{4}{9}x^2y^2-\frac{5}{6}x^2y^2=\\(\frac{1}{3}+\frac{4}{9}-\frac{5}{6})x^2y^2=\\\frac{6+2-3}{18}=\\\frac{5}{18}$

g) $ay+\frac{3}{4}ay-4ay=\\(1+\frac{3}{4}-4)ay=\\\frac{4+3-16}{4} =\\\frac{-9}{4}$

h) $0,9ab^3+2,5ab^3-5,2ab^3=\\(0,9+2,5-5,2)ab^3=\\\\-1,8ab^3$