Question

2 considere a função f (x)= 3x ao quadrado+1.​

Answer 1

Explicação passo-a-passo:

f(x)=3x²+1

$a)\\ f(4)=3(4)^2+1\\ f(4)=3(16)+1\\ f(4)=48+1\\ f(4)=49\\ \\ b)\\ f(-3)=3(-3)^2+1\\ f(-3)=3(9)+1\\ f(-3)=27+1\\ f(-3)=28\\ \\ c)\\ f(0,5)=3(0,5)^2+1\\ f(0,5)=3(0,25)+1\\ f(0,5)=0,75+1\\ f(0,5)=1,75\\ \\ d)\\ f(\sqrt{6} )=3(\sqrt{6} )^2+1\\ f(\sqrt{6} )=3(6)+1\\ f(\sqrt{6} )=18+1\\ f(\sqrt{6} )=19$