Question

2. Calcule:
a. (4 + 3i) + (2 + 4i)
c. (5 + 3i). (3 + 2i)
b. (8 + 5i) - (2 + 4i)
d.
(3+1)
(6+2i)​

Answer 1

a) (4 + 3i) + (2 + 4i) = 4 + 3i + 2 + 4i = 6 + 7i

b) (8 + 5i) - (2 + 4i) = 8 + 5i - 2 - 4i = 6 + i

c) (5 + 3i) · (3 + 2i) = 15 + 10i + 9i + 6i² = 15 + 19i + 6i²

d) $\frac{3+i}{6+2i} = \frac{3+i}{2(3+i)}=\frac{1}{2}$