Question

2 (×-5)-3>_6×+2
como resolver

Answer 1

2 (×-5)-3 ≥ 6×+2
2x - 10 - 3 ≥ 6x + 2
2x - 6x ≥ 2 + 3 + 10
- 4x ≥ 15(-1)
4x ≤ - 15
x ≤ - 15/4 ou x ≤ - 3,75

Um abraço.

Answer 2

Olá!
 
  
    $2(x-5)-3\geqslant 6x+2\Leftrightarrow 2x-10-3\geqslant 6x+2\Leftrightarrow \\ \\ \Leftrightarrow (2x-2x)-13\geqslant 6x+2-2x\Leftrightarrow -13-2\geqslant 4x+(2-2)\Leftrightarrow \\ \\ \Leftrightarrow-15\geqslant 4x\Leftrightarrow -\dfrac{15}{4}\geqslant x.\\ \\ \\ \text{A solu\c c\~ao {\bf{S}} \'e} \\ S=\left\{x\in\mathbb{R}:x\leqslant -\frac{15}{4}\right\} = \left]-\infty,-\frac{15}{4}\right].$



Bons estudos!