Question

16. Sabendo que A e B são dois polinômios, se A - B = 0, então: (

A) (A + B) - B = 0.
(B) (A-B) - B=0.
(C) A - B = A + (-B) = 0.
(D) -A + (-B) = 0.
(E) -A- (+B) = 0.​

Answer 1

✅ Verificando as identidades polinomiais:

Se A e B são dois polinômios, tais que:

                       $\Large\displaystyle\begin{gathered} A - B = 0\end{gathered}$

Então, isso implica que:

     $\Large\displaystyle\begin{gathered} A = B\:\:\:\textrm{com}\:\:A\neq0\:\:e\:\:B\neq0\end{gathered}$

Desse modo devemos verificar se as seguintes respostas são verdadeiras:

• A)

          $\Large\displaystyle\begin{gathered} (A + B) - B = 0\end{gathered}$

              $\Large\displaystyle\begin{gathered} A + B - B = 0\end{gathered}$

                                  $\Large\displaystyle\begin{gathered} A = 0\end{gathered}$  

            $\Large\displaystyle\begin{gathered} \textrm{Se}\:\:A = B\end{gathered}$

                                  $\Large\displaystyle\begin{gathered} B = 0\end{gathered}$  

           Portanto é:

                                   $\Large\displaystyle\begin{gathered} \textrm{Falso}\end{gathered}$                              

• B)

           $\Large\displaystyle\begin{gathered} (A - B) - B = 0\end{gathered}$

              $\Large\displaystyle\begin{gathered} A - B - B = 0\end{gathered}$

                      $\Large\displaystyle\begin{gathered} A - 2B = 0\end{gathered}$

           $\Large\displaystyle\begin{gathered} \textrm{Se}\:\:A = B\end{gathered}$

                      $\Large\displaystyle\begin{gathered} A - 2A = 0\end{gathered}$

                               $\Large\displaystyle\begin{gathered} -A = 0\end{gathered}$

            Portanto é:

                                    $\Large\displaystyle\begin{gathered} \textrm{Falso}\end{gathered}$

• C)

           $\Large\displaystyle\begin{gathered} A - B = A + (-B) = 0\end{gathered}$

                   $\Large\displaystyle\begin{gathered} A - B = A - B = 0\end{gathered}$

           $\Large\displaystyle\begin{gathered} \textrm{Se}\:\:A = B\end{gathered}$

                    $\Large\displaystyle\begin{gathered} A - A = A - A = 0\end{gathered}$

           Portanto:

                                 $\Large\displaystyle\begin{gathered} \textrm{Positivo}\end{gathered}$

• D)

           $\Large\displaystyle\begin{gathered} -A + (-B) = 0\end{gathered}$

                   $\Large\displaystyle\begin{gathered} -A - B = 0\end{gathered}$

                             $\Large\displaystyle\begin{gathered} -A = B\end{gathered}$

           $\Large\displaystyle\begin{gathered} \textrm{Se}\:\:A = B\end{gathered}$

                              $\Large\displaystyle\begin{gathered} -A = A\end{gathered}$

           Portanto:

                                   $\Large\displaystyle\begin{gathered} \textrm{Falso}\end{gathered}$

• E)  

          $\Large\displaystyle\begin{gathered} -A - (+B) = 0\end{gathered}$

                  $\Large\displaystyle\begin{gathered} -A - B = 0\end{gathered}$

                            $\Large\displaystyle\begin{gathered} -A = B\end{gathered}$

           $\Large\displaystyle\begin{gathered} \textrm{Se}\:\:A = B\end{gathered}$

                            $\Large\displaystyle\begin{gathered} -A = A\end{gathered}$

            Portanto:

                                    $\Large\displaystyle\begin{gathered} \textrm{Falso}\end{gathered}$

$\LARGE\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{\:\:\:Bons \:estudos!!\:\:\:Boa\: sorte!!\:\:\:}}}\end{gathered} }$

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Answer 2

Explicação passo-a-passo:

अलफाबेटिकल छहह ओ-नान कीहह अख एरर जाब नमबर आव अख सीसटम लूकिल सीसटम एरर आव परायीस कूट जूरीथ अख एरर इस इ बापत अख ईसतिमाल परीस सेट अप करिथ करिव टरानज़ेकशन नव कॊरीव मसलन अख अख नॊव ईनवायीस फायिल पूसट ईनफारमेशन ईफ़फ कॊरिव चॊरीव फारवड करिव