Question

√16 elevado a 3 + √54 elevado a 3
----------------------------------------
dividido por √125 elevado a 3

Answer 1

$\frac{ \sqrt[3]{16}+ \sqrt[3]{54} }{ \sqrt[3]{125} }=$$\frac{ \sqrt[3]{2.8}+ \sqrt[3]{2.27} }{ \sqrt[3]{ 5^{3} } } =$$\frac{\sqrt[3]{2}*\sqrt[3]{8}+\sqrt[3]{2}*\sqrt[3]{27}}{\sqrt[3]{5^3}} =$$\frac{\sqrt[3]{2}*\sqrt[3]{2^3}+\sqrt[3]{2}*\sqrt[3]{3^3}}{\sqrt[3]{5^3}} =$$\frac{2\sqrt[3]{2}+3\sqrt[3]{2}}{5} =$$\frac{5\sqrt[3]{2}}{5}=$$\sqrt[3]{2}$