15 Pontos
Calcule o valor de x nas proporções:
a) 6/x = 9/12
b) 2x/3= -24/15
c) 3/4= 5x/20
d)x+3/4= 12/6
Soluções para a tarefa
Respondido por
14
Oi,
basta multiplicar cruzado e efetuar as operações>
![\dfrac{6}{x}= \dfrac{9}{12}\\\\
6\cdot12=9\cdot x\\
72=9x\\
x=72/9\\
x=8 \dfrac{6}{x}= \dfrac{9}{12}\\\\
6\cdot12=9\cdot x\\
72=9x\\
x=72/9\\
x=8](https://tex.z-dn.net/?f=+%5Cdfrac%7B6%7D%7Bx%7D%3D+%5Cdfrac%7B9%7D%7B12%7D%5C%5C%5C%5C%0A6%5Ccdot12%3D9%5Ccdot+x%5C%5C%0A72%3D9x%5C%5C%0Ax%3D72%2F9%5C%5C%0Ax%3D8++)
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![\dfrac{2x}{3}=- \dfrac{24}{15}\\\\
2x\cdot15=3\cdot(-24)\\
15x=-72\\\\
x= -\dfrac{72}{15}= \dfrac{72\div3}{15\div3}= -\dfrac{24}{5} \\\\\\
x=- \dfrac{24}{5} \dfrac{2x}{3}=- \dfrac{24}{15}\\\\
2x\cdot15=3\cdot(-24)\\
15x=-72\\\\
x= -\dfrac{72}{15}= \dfrac{72\div3}{15\div3}= -\dfrac{24}{5} \\\\\\
x=- \dfrac{24}{5}](https://tex.z-dn.net/?f=+%5Cdfrac%7B2x%7D%7B3%7D%3D-+%5Cdfrac%7B24%7D%7B15%7D%5C%5C%5C%5C%0A2x%5Ccdot15%3D3%5Ccdot%28-24%29%5C%5C%0A15x%3D-72%5C%5C%5C%5C%0Ax%3D+-%5Cdfrac%7B72%7D%7B15%7D%3D+%5Cdfrac%7B72%5Cdiv3%7D%7B15%5Cdiv3%7D%3D+-%5Cdfrac%7B24%7D%7B5%7D+%5C%5C%5C%5C%5C%5C%0Ax%3D-+%5Cdfrac%7B24%7D%7B5%7D++++)
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![\dfrac{3}{4}= \dfrac{5x}{20}\\\\
3\cdot20=4\cdot5x\\
60=20x\\\\
x= \dfrac{60}{20}\\\\
x=3 \dfrac{3}{4}= \dfrac{5x}{20}\\\\
3\cdot20=4\cdot5x\\
60=20x\\\\
x= \dfrac{60}{20}\\\\
x=3](https://tex.z-dn.net/?f=+%5Cdfrac%7B3%7D%7B4%7D%3D+%5Cdfrac%7B5x%7D%7B20%7D%5C%5C%5C%5C%0A3%5Ccdot20%3D4%5Ccdot5x%5C%5C%0A60%3D20x%5C%5C%5C%5C%0Ax%3D+%5Cdfrac%7B60%7D%7B20%7D%5C%5C%5C%5C%0Ax%3D3+++)
_____________
![\dfrac{x+3}{4}= \dfrac{12}{6}\\\\
\dfrac{x+3}{4}=2\\\\
x+3=4\cdot2\\
x+3=8\\
x=8-3\\
x=5 \dfrac{x+3}{4}= \dfrac{12}{6}\\\\
\dfrac{x+3}{4}=2\\\\
x+3=4\cdot2\\
x+3=8\\
x=8-3\\
x=5](https://tex.z-dn.net/?f=+%5Cdfrac%7Bx%2B3%7D%7B4%7D%3D+%5Cdfrac%7B12%7D%7B6%7D%5C%5C%5C%5C%0A+%5Cdfrac%7Bx%2B3%7D%7B4%7D%3D2%5C%5C%5C%5C%0Ax%2B3%3D4%5Ccdot2%5C%5C%0Ax%2B3%3D8%5C%5C%0Ax%3D8-3%5C%5C%0Ax%3D5+++)
Tenha ótimos estudos, e espero ter ajudado^^
basta multiplicar cruzado e efetuar as operações>
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Tenha ótimos estudos, e espero ter ajudado^^
korvo:
se não conseguir me chama que eu faço ^^
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