Question

13- Calcule as raízes:

Answer 1

Temos que uma propriedade da radiciação consiste em:

$\sqrt{\dfrac{a}{b}} = \dfrac{\sqrt{a}}{\sqrt{b}}$

Vamos aplicá-la em seu exercício:

$a) \ \sqrt{\dfrac{100}{9}} = \dfrac{\sqrt{100}}{\sqrt{9}} = \dfrac{10}{3}\\\\\\b) \a) \ \sqrt{\dfrac{100}{9}} = \dfrac{\sqrt{100}}{\sqrt{9}} = \dfrac{10}{3}\\\\\\b) \ -\sqrt{\dfrac{1}{81}} = -\dfrac{\sqrt{1}}{\sqrt{81}} = -\dfrac19\\\\\\c) \ -\sqrt{\dfrac{49}{16}} = -\dfrac{\sqrt{49}}{\sqrt{16}} = -\dfrac74\\\\\\d) \ \sqrt{\dfrac{4}{25}} = \dfrac{\sqrt{4}}{\sqrt{25}} = \dfrac45\\\\\\e) \ \sqrt{\dfrac{121}{100}} + \sqrt{\dfrac{81}{25}} = \dfrac{11}{10} + \dfrac{9}{5} = \dfrac{11+18}{10} = \dfrac{29}{10}$

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