Question

11 termo da P.G em A1=1 e q=-2

Answer 1

$> resolucao \\ \\ \geqslant progressao \: \: geometrica \\ \\ an = a1 \times q {}^{n - 1} \\ an = 1 \times ( - 2) {}^{11 - 1} \\ an = 1 \times ( - 2) {}^{10} \\ an = 1 \times 1024 \\ an = 1024 \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant$