Question

10) Dada a lei che formação: A = (aij)2x2/aij = -i +j³, calcule 2A e teremos:​

Answer 1

Resposta:

Explicação passo a passo:

Resolvendo:

$i=linha\\j=coluna\\\\A=\left[\begin{array}{ccc}a_{1,1} &a_{1,2}\\a_{2,1}&a_{2,2}\\\end{array}\right] \\\\\\\left[\begin{array}{ccc}-1+1^{3} &-1+2^{3} \\-2+1^{3} &-2+2^{3} \\\end{array}\right] =\\\\\\\left[\begin{array}{ccc}-1+1 &-1+8 \\-2+1&-2+8} \\\end{array}\right] =\\\\\\\left[\begin{array}{ccc}0 &7\\-1&6} \\\end{array}\right]$

$2A=2\left[\begin{array}{ccc}0 &7\\-1&6} \\\end{array}\right]=\left[\begin{array}{ccc}0 &14\\-2&12} \\\end{array}\right]$

Resposta:

$\left[\begin{array}{ccc}0 &14\\-2&12} \\\end{array}\right]$

Espero ter ajudado!

Desculpe qualquer erro.